Consider the following orbitals, $3 s, 2 p_{x}, 4 d_{x y}, 4 d_{z^{2}}, 3 d_{x^{2} - y^{2}}, 3 p_{y}, 4 s, 4 p_{z}$ and find total number of orbital(s) having even number of nodal plane.

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Solution

$3 s = 0 Nodal plane$
$4 d_{z^{2}} = 0 Nodal plane$
$4 s = 0 Nodal plane$
$2 p_{x} = 1 Nodal plane$
$3 d_{x^{2} - y^{2}} = 2 Nodal plane$
$4 p_{z} = 1 Nodal plane$
$4 d_{x y} = 2 Nodal plane$
$3 p_{y}$ :1 Nodal plane
So, the orbitals having even number of nodal plane are $3 s, 4 d_{x y}, 4 d_{z^{2}}, 3 d_{x^{2} - y^{2}}, 4 s$

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