Arrange the fractions given below in order from least to greatest (Ascending order)
$2 \frac{1}{3}, 3 \frac{1}{3}, 4 \frac{1}{3}$

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Solution

The improper fraction of $2 \frac{1}{3}, 3 \frac{1}{3}, 4 \frac{1}{3}$ is $\frac{7}{3}, \frac{10}{3}, \frac{13}{3}$
Since, the denominator of given fraction are same
$∴$ The ascending order of $2 \frac{1}{3}, 3 \frac{1}{3}, 4 \frac{1}{3}$ is $2 \frac{1}{3}, 3 \frac{1}{3}, 4 \frac{1}{3}$

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