Question

Arrange the oxides of nitrogen in increasing order of oxidation state of $N$ from +1 to +5:

• A. $N_{2}O<N_2{O}_3<N{O}_2<N_2{O}_5<NO$
• B. $N_{2}O<NO<N_2{O}_3<N{O}_2<N_2{O}_5$
• C. $N_2{O}_5<N{O}_2<N_2{O}_3<NO<N_{2}O$
• D. $NO<N_{2}O<N{O}_2<N_2{O}_3<N_2{O}_5$

Answer 1

Answer: (B)

$N_{2}O<NO<N_2{O}_3<N{O}_2<N_2{O}_5$

We know that the charge on oxygen is $-2$.

Different oxides of nitrogen has different number of oxygen atoms. Hence the oxidation states of nitrogen in its Oxides are as follows

$N_{2}O\to +1,NO\to +2$
$N_2{O}_3\to +3,N{O}_2\to +4,N_2{O}_5\to +5$

Therefore, option B is the correct answer of this question.