Question

Arrange the trapeziums in decreasing order(from top) of its area for given sum of parallel sides and altitude.

• A. 24, 10
• B. 18, 12
• C. 20, 8
• D. 22, 14

Answer 1

Area of a trapezium
$=\frac{1}{2}\times (a+b)\times h$
where a and b are the parallel sides and h is the height.

Hence, area of given trapeziums will be
$\frac{1}{2}\times 24\times 10$ = 120 $c{m}^2$
$\frac{1}{2}\times 18\times 12$ = 108 $c{m}^2$
$\frac{1}{2}\times 20\times 8$ = 80 $c{m}^2$
$\frac{1}{2}\times 22\times 14$ = 154 $c{m}^2$