As a submarine descends into the deep ocean, the pressure it must withstand increase. At an altitude of $- 700$ meters, the pressure is $50$ atm (atmosphere), and at altitude of $- 900$ meters, the pressure is $70$ atm. For every $10$ meters the submarine descends, the pressure it faces increase by $n$ , where $n$ is a constant. What is the value of $n$ ?

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Solution

The correct option is B $1$
for the fall of $200 m e t e r s$ the rise of pressure is $20 a t m$ , then for fall of $10 m e t e r s$ the ris ewill be $1 a t m$ by using proportions.the value of $n = 1$

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The correct option is B 1for the fall of 200meters the rise of pressure is 20atm, then for fall of 10meters the ris ewill be 1atm by using proportions.the value of n=1

The correct option is B $1$
for the fall of $200 m e t e r s$ the rise of pressure is $20 a t m$ , then for fall of $10 m e t e r s$ the ris ewill be $1 a t m$ by using proportions.the value of $n = 1$