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Question

As given in the figure two blocks A & B of weight 20 N and 100 N respectively are in equilibrium. These are being pressed against a wall by force F as shown. If the coefficient of friction between the two blocks is 0.1 and between block B and the wall is 0.15, the frictional force applied by wall on block B is (f2) and the frictional force applied by block B on block A is (f1).

A
f2=120 N
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B
f2=150 N
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C
f1=100 N
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D
f1=20 N
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Solution

The correct options are
A f2=120 N
D f1=20 N
FBD of block A


For equilibrium of A
f1=WA
f1=20 N ...(1)

To balance WA force friction will act in upward direction)

FBD of block B


For equilibrium of B
f2=f1+WB
f2=20+100
f2=120 N

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