Question

As per Gauss law
$\int E.dS=\frac{q_{in}}{{ϵ}_0}$
Which of the following is true about this

• A. This is valid for only symmetrical surface only
• B. $E$ is the electric field to the charge inside the surface
• C. Electric flux on the closed surface due to outside charge is always zero
• D. none of the above

Answer 1

The correct option is B $E$ is the electric field to the charge inside the surface

Given Gauss Law :-

$\int E.da=\frac{Q_{inc}}{{\epsilon }_0}$

As we know that according to Gauss law total fluk through a symmetrical surface is $Q_{inc}$ by ${\epsilon }_0$.

Here Symmetrical surface has its significance because if we can choose unsymmetrical value there will be different value of E (electric field) on the surface.

$\therefore \int E.da=\frac{Q_{inc}}{{\epsilon }_0}$will be wrong.

$\therefore$ Option (A) is correct.

From the definition we can conclude that one electric field on the surface at Gaussion figure, depends upon the charge enclved by the surface.

$\therefore$ That's why Option (B) is correct.