As shown in the figure, Avinash is standing near his house. He can choose from two roads to go to school. Which way is
shorter? Explain why.

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Solution

In any triangle, the sum of the lengths of any two sides of a triangle is always greater than the third side.
Therefore, in △ABC, AC < AB + BC.
Hence, the shortest way to reach school is via AC.

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As shown in the figure, Avinash is standing near his house. He can choose from two roads to go to school. Which way is shorter? Explain why.

In any triangle, the sum of the lengths of any two sides of a triangle is always greater than the third side. Therefore, in △ABC, AC < AB + BC. Hence, the shortest way to reach school is via AC.

As shown in the figure, Avinash is standing near his house. He can choose from two roads to go to school. Which way is
shorter? Explain why.

In any triangle, the sum of the lengths of any two sides of a triangle is always greater than the third side.
Therefore, in △ABC, AC < AB + BC.
Hence, the shortest way to reach school is via AC.