As shown to the right, two blocks with masses $m$ and $M (M > m)$ are pushed by a force $F$ in both Case $I$ and Case $I I$ . The surface on which blocks lie, is horizontal and frictionless. Let $R_{I}$ be the force that $m$ exerts on $M$ in case $I$ and $R_{I} I$ be the force that $m$ exerts on $M$ in case $I I$ . Which of the following statements is true?

R_{I} = R_{I I} = F

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R_{I} = R_{I I}

and is not equal to zero or

F

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R_{I} < R_{I I}

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R_{I} > R_{I I}

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Solution

The correct option is C $R_{I} < R_{I I}$
Acceleration of all blocks in both cases is the same and $a = \frac{F}{M + m}$

In case $I$ : required normal reaction $R_{I}$ is equal to net force on block of mass $m$ .
$R_{I} = m a$

In case $I I$ : required normal reaction $R_{I I}$ is equal to net force on block of mass $M$ .
$R_{I I} = M a$

Hence, $R_{I I} > R_{I}$

Final Answer : c

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