Question

As the temperature is raised from ${20}^{\circ }C$ to ${40}^{\circ }C$. The average kinetic energy of neon atoms changes by a factor of which of the following:

• A. $2$
• B. $\sqrt{\frac{313}{293}}$
• C. $\frac{313}{293}$
• D. $\frac{1}{2}$

Answer 1

The correct option is C

$\frac{313}{293}$

Average kinetic energy $\propto$ Temperature in Kelvin

$\frac{K{E}_{40}}{K{E}_{20}}=\frac{\frac{3}{2}\times nR\times 313}{\frac{3}{2}\times nR\times 293}$

$\frac{K{E}_{40}}{K{E}_{20}}=\frac{T_2}{T_1}=\frac{40+273}{20+273}=\frac{313}{293}$