Question

As the temperature is raised from ${20}^{o}C$ to ${40}^{o}C$, the average kinetic energy of neon atoms changes by a factor:

• A. $2$
• B. $\sqrt{\frac{313}{293}}$
• C. $\frac{313}{293}$
• D. $\frac{1}{2}$

Answer 1

The correct option is C $\frac{313}{293}$

$K.E=\frac{3}{2}RT$

$K.E$ is directly proportional to $T$

${20}^{o}C⟶{40}^{o}C$

Using formula,

$K.E=\frac{3}{2}RT$

$\frac{K_{40}}{K_{20}}=\frac{T_{40}}{T_{20}}$

$=\frac{273+40}{273+20}$

$=\left(\frac{313}{293}\right)$

Hence, option $C$ is correct answer.