Assertion :20 g of argon (atomic mass of $A r = 40$ ) occupies volume of 22400 $c m^{3}$ at STP. Reason: 4 g of helium (atomic mass of $H e = 4$ ) occupies a volume of 22400 $c m^{3}$ at STP.

Both Assertion and Reason are correct and Reason is the correct explanation for Assertion

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Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion

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Assertion is incorrect but Reason is correct

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Both Assertion and Reason are incorrect

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Solution

The correct option is C Assertion is incorrect but Reason is correct
Moles of Argon $= \frac{20}{40} = 0.5$ of $A r$

$1$ mole of any gas occupies ${22400 c m}^{3}$ at $S T P$

$∴$ $0.5$ moles of $A r$ should contain $0.5 \times 22400 = 11200 {c m}^{3}$ at $S T P$ .

Moles of $H e$ $= \frac{4}{4} = 1$ mole

$∴$ $1$ mole of $H e$ must occupy ${22400 c m}^{3}$ at $S T P$ .

Hence, option $C$ is correct.

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Assertion :20 g of argon (atomic mass of Ar=40) occupies volume of 22400 cm3 at STP. Reason: 4 g of helium (atomic mass of He=4) occupies a volume of 22400 cm3 at STP.

Assertion :20 g of argon (atomic mass of $A r = 40$ ) occupies volume of 22400 $c m^{3}$ at STP. Reason: 4 g of helium (atomic mass of $H e = 4$ ) occupies a volume of 22400 $c m^{3}$ at STP.