Assertion :A parallel plate capacitor is first charged and then distance between the plates is increased. In this process electric field between the plates remains the same, while potential difference gets decreased. Reason: $E = \frac{q}{A ε_{0}}$ and $V = \frac{q}{A d ε_{0}}$ . Since, q remains same, E will remain same while V will decrease.

Both Assertion and Reason are correct and Reason is the correct explanation for Assertion

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Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion

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Assertion is correct but Reason is incorrect

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Assertion is incorrect but Reason is correct

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Solution

The correct option is A Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
As the total charge is conserved so charge q remains the same.
The filed is $E = \frac{q}{A ϵ_{0}}$
As q same, so E will the same.
The potential difference is $V = E d$
As d increases so V will increase.

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The correct option is A Both Assertion and Reason are correct and Reason is the correct explanation for AssertionAs the total charge is conserved so charge q remains the same.The filed is E=qAϵ0 As q same, so E will the same.The potential difference is V=EdAs d increases so V will increase.