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Equivalent, Molar Conductivity and Cell Constant

Assertion : ...

Question

Assertion : $[C o (e n)_{2} (N H_{3}) B r] S O_{4}$ has lower electrical conductivity as compared to $[C o (e n)_{2} (N H_{3}) S O_{4}] B r$ . Reason: Both the ions produce the same number of ions in solution.

A

Both Assertion and Reason are true and the Reason is a correct explanation of Assertion.

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B

Both Assertion and Reason are true but Reason is not a correct explanation of Assertion.

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C

Assertion is true but the Reason is false.

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D

Assertion is false but the Reason is true.

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Solution

The correct option is D Assertion is false but the Reason is true.
$C o (e n)_{2} (N H_{3}) B r] S O_{4}$ has higher electrical conductivity as compared to $[C o (e n)_{2} (N H_{3}) S O_{4}] B r$ . Both compounds give two ions in the solution. But the charge on sulfate ion is twice the charge on bromide ion. Hence sulfate ion has higher electrical conductivity than bromide ion. Same is true for the complex cations.

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