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Byju's Answer

Standard XII

Chemistry

Empirical & Molecular Formula

Assertion :Em...

Question

Assertion :Empirical formula of glucose is $H C H O$ .
Reason: Molecular formula of glucose will also be equal to $H C H O$ .

Both Assertion and Reason are correct and Reason is the correct explanation for Assertion

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Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion

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Assertion is correct but Reason is incorrect

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Both Assertion and Reason are incorrect

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Solution

The correct option is C Assertion is correct but Reason is incorrect
Molecular formula of glucose is $C_{6} H_{12} O_{6}$
This is (HCHO) $_{6}$
Therefore its empirical formula is HCHO.

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Similar questions

Q. Assertion: The compressibility factor for

H_{2}

and

H e

(1 + \frac{P b}{R T})

Reason: The compressibility factor for

H_{2}

and

H e

can be derived from Van der Waal's equation.

Assertion (A) Order and molecularity are same.

Reason (R) Order is determined experimentally and molecularity is the sum of the stoichimetric coeffcient of rate determining elementary step.

(a) Both assertion and reason are correct and the reason is correct explanation of assertion
(b) Both assertion and reason are correct, but reason does not explain assertion.
(c) Assertion is correct, but reason is incorrect
(d) Both assertion and reason are incorrect
(e) Assertion is incorrect but reason is correct.

ASSERTION: n-Pentane and n-Hexane belong to a homologous series.

REASON: n-Pentane and n-Hexane belong to the same class of hydrocarbons and they differ by a - $C H_{2}$ - group.

Assertion – The non-fusible impurities present in iron ore are removed by $C a C O_{3}$ .

Reason: $C a C O_{3}$ which decomposes into $C a O$ and $C O_{2}$ . The $C a O$ formed reacts with $S i O_{2}$ to remove silica

Q. Assertion: The impurities such as

{SiO}_{2}

present in iron ore is removed by

{CaCO}_{3}

.

Reason:

CaO

formed by decomposition of

{CaCO}_{3}

reacts with

{SiO}_{2}

to form slag.

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Assertion :Empirical formula of glucose is HCHO. Reason: Molecular formula of glucose will also be equal to HCHO.

The correct option is C Assertion is correct but Reason is incorrectMolecular formula of glucose is C6H12O6This is (HCHO)6Therefore its empirical formula is HCHO.

Assertion :Empirical formula of glucose is $H C H O$ .
Reason: Molecular formula of glucose will also be equal to $H C H O$ .

The correct option is C Assertion is correct but Reason is incorrect
Molecular formula of glucose is $C_{6} H_{12} O_{6}$
This is (HCHO) $_{6}$
Therefore its empirical formula is HCHO.