wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Assertion :I: The equation f(x)=4x5+20x−9=0 has only one real root. Reason: II: f′(x)=20x4+20=0 has no real root.

A
Statement I is true,Statement II is also true; Statement II is the correct explanation of Statement I
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
Statement I is true,Statement II is also true; Statement II is not the correct explanation of Statement I
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Statement I is true,Statement II is false
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Statement I is false,Statement II is true
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A Statement I is true,Statement II is also true; Statement II is the correct explanation of Statement I
Given equation is 4x5+20x9=0
Fifth degree equation must have at least one real root.
If it had two real roots, f(x)=0 must have one real root.
Hence, Option A is correct.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Relation of Roots and Coefficients
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon