Assertion -If nA-3-nB-6- then maximum number of elements of nA - B-9 Reason- nA - B will be maximum if nA - B is minimum-

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Standard VI

Mathematics

Cardinality

Assertion :If...

Question

Assertion :If $n (A) = 3, n (B) = 6$ , then maximum number of elements of $n (A \cup B) = 9$ Reason: $n (A \cup B)$ will be maximum if $n (A \cap B)$ is minimum.

Both Assertion and Reason are correct and Reason is the correct explanation for Assertion

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Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion

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Assertion is correct but Reason is incorrect

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Both Assertion and Reason are incorrect

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Solution

The correct option is A Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
$n (A \cup B) = n (A) + n (B) - n (A \cap B)$

$∴ n (A \cup B) = n (A) + n (B)$ for maximum of $n (A \cup B)$

Then the value of $n (A \cap B) = 0$

$n (A \cup B) = 3 + 6 = 9$

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Assertion :If n(A)=3,n(B)=6, then maximum number of elements of n(A∪B)=9 Reason: n(A∪B) will be maximum if n(A∩B) is minimum.

The correct option is A Both Assertion and Reason are correct and Reason is the correct explanation for Assertionn(A∪B)=n(A)+n(B)−n(A∩B)∴n(A∪B)=n(A)+n(B) for maximum of n(A∪B) Then the value of n(A∩B)=0n(A∪B)=3+6=9

Assertion :If $n (A) = 3, n (B) = 6$ , then maximum number of elements of $n (A \cup B) = 9$ Reason: $n (A \cup B)$ will be maximum if $n (A \cap B)$ is minimum.

The correct option is A Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
$n (A \cup B) = n (A) + n (B) - n (A \cap B)$

$∴ n (A \cup B) = n (A) + n (B)$ for maximum of $n (A \cup B)$

Then the value of $n (A \cap B) = 0$

$n (A \cup B) = 3 + 6 = 9$