Question

Assertion :In a series R-L-C Circuit the voltage across resistor,inductor and capacitor are 8 V, 16 V and 10 V respectively.The resultant emf of circuit is 10 V. Reason: Resultant emf of circuit is given by relation $E=\sqrt{{V_R}^2+(V_L-V_C{)}^2}$

• A. Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
• B. Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
• C. Assertion is correct but Reason is incorrect
• D. Both Assertion and Reason are incorrect

Answer 1

The correct option is A Both Assertion and Reason are correct and Reason is the correct explanation for Assertion

Solution:-

For series R-L-C circuit, we have given;

$V_R=8V{V}_L=16V{V}_C=10V$

E = 10V

Phasor diagram corresponding to them:-

E = $\sqrt{{V_R}^2+(V_L-V_C{)}^2}=\sqrt{8^2+(16-10{)}^2}=\sqrt{100}=10$

Option A is correct.