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Question

Assertion :In each of the three planes determined by two of the lines OA,OB,OC (O being the origin), a straight line is drawn through O perpendicular to the third line.
The three lines so determined are coplanar. Reason: (a×b)×c+(b×c)×a+(c×a)×b=0, where OA=a,OB=b and OC=c.

A
Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
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B
Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
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C
Assertion is correct but Reason is incorrect
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D
Both Assertion and Reason are incorrect
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Solution

The correct option is B Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
The plane containg OA and OB is r.(a×b)=0
Any line in this plane is perpendicular to the vector a×b.
Thus the line in this plane perpendicular to OC is parallel to the vector (a×b)×c
So the equation of three lines are
r=t(a×b)×c,r=p(b×c)×a and r=r(c×a)×b
But (a×b)×c+(b×c)×a+(c×a)×b=0
So that three vectors (a×b)×c,(b×c)×a,(c×a)×b are coplanar

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