Question

Assertion :In projectile motion if particle is projected with speed $u$, then speed of particle at height $h$ would be $\sqrt{u^2-2gh.}$ Reason: If particle is projected with vertical component of velocity, $u_y.$ Then vertical component at the height $h$ would be $\pm \sqrt{u_y^2-2gh.}$

• A. Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
• B. Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
• C. Assertion is correct but Reason is incorrect
• D. Both Assertion is incorrect but Reason is correct.

Answer 1

The correct option is B Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion

For the assertion: $\sqrt{u_y^2-2gh+u_x^2}=\sqrt{u^2-2gh}$
For the reason:
vertical component of velocity at height h :$\sqrt{u_y^2-2gh}$