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Question

Assertion :Let |a|=|b|=|c|=1 such that a+b+c=0 then a.b+b.c+c.a=32 Reason: (p+q)2=|p|2+|q|2+2p.q

A
Both Assertion & Reason are individually true & Reason is correct explanation of Assertion
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B
Both Assertion & Reason are individually true but Reason is not the correct explanation of Assertion
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C
Assertion is true but Reason is false
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D
Assertion is false but Reason is true
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Solution

The correct option is A Both Assertion & Reason are individually true & Reason is correct explanation of Assertion
Given
¯¯¯a=¯¯b=¯¯c=1
¯¯¯a+¯¯b+¯¯c=¯¯¯0
So,
(¯¯¯a+¯¯b+¯¯c)2=0
¯¯¯a2+¯¯b2+¯¯c2+2(¯¯¯a¯¯b+¯¯b¯¯c+¯¯c¯¯¯a)=0
¯¯¯a¯¯b+¯¯b¯¯c+¯¯c¯¯¯a=32

Assertion(A) and Reason(R) both are true and Reason(R) is feasible explanation of a Assertion(A)

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