Assertion :Let f:R→R, f(x)=x3+x2+100x+5sinx, then f(x) is bijective. Reason: 3x2+2x+95>0x∈R.
A
Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
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B
Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
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C
Assertion is correct but Reason is incorrect
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D
Assertion is incorrect but Reason is correct
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Solution
The correct option is B Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion We have, f(x)=x3+x2+100x+5sinx Since −1≤sinx≤1 and −∞<x3+x2+100x<∞ Range of f is R which is equal to co-domain ⇒f is onto function. Now f′(x)=3x2+2x+100+5cosx Also −1≤cosx≤1 ⇒f′(x)=3x2+2x+100+5(−1)=3x2+2x+95 Discriminant of above quadratic is 4−4(3)(95)<0 which means f′(x)>0∀x∈R⇒f is increasing function ⇒f is an one-one function Hence both statements are correct but Reason is not correct explanation of Assertion.