Assertion: Second group metals are precipitated as their sulphides in the presence of dilute $H C l$ .
Reason: Sulphides of $3^{r d}, 4^{t h}, 5^{t h}$ and $6^{t h}$ group metals have very low solubility products compared to those of second group metals.

Both Assertion and Reason are correct and Reason is the correct explanation of Assertion

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Both Assertion and Reason are correct but Reason is not the correct explanation of Assertion

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Assertion is correct but Reason is not correct

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Assertion is not correct but Reason is correct

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Both Assertion and Reason are not correct

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Solution

The correct option is C Assertion is correct but Reason is not correct
The sulphides of higher group metals remain in solution not because of their lower solubility products, but because of their higher solubility products than those of group 2 cations. Due to the common ion effect of $H^{+}$ (from HCl added in group 1) the dissociation of $H_{2} S$ is suppressed; hence the $S^{2 -}$ ion concentration is very low, which is just enough to precipitate $2^{n d}$ group metal sulphides whose $K_{s p}$ is relatively low.

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Assertion: Second group metals are precipitated as their sulphides in the presence of dilute HCl.Reason: Sulphides of 3rd,4th,5th and 6th group metals have very low solubility products compared to those of second group metals.

Assertion: Second group metals are precipitated as their sulphides in the presence of dilute $H C l$ .
Reason: Sulphides of $3^{r d}, 4^{t h}, 5^{t h}$ and $6^{t h}$ group metals have very low solubility products compared to those of second group metals.