    Question

# Assertion :Suppose four distinct positive numbers a1,a2,a3,a4 are in GP. Let b1=a1,b2=b1+a2,b3=b2+a3 and b4=b3+a4.STATEMENT- 1: The numbers b1,b2,b3,b4 are neither in AP nor in GP, and Reason: STATEMENT- 1: The numbers b1,b2,b3,b4 are in HP.

A
STATEMENT- 1 is True, STATEMENT- 2 is True; STATEMENT- 2 is a correct explanation for STATEMENT- 1.
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B
STATEMENT- 1 is True, STATEMENT- 2 is True; STATEMENT- 2 is NOT a correct explanation for STATEMENT- 1.
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C
STATEMENT- 1 is True, STATEMENT- 2 is False.
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D
STATEMENT- 1 is False, STATEMENT- 2 is True.
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Solution

## The correct option is C STATEMENT- 1 is True, STATEMENT- 2 is False.∵a1,a2,a3 and a4are in G.P with common ratio ′r′⇒a1=a,a2=ar,a3=ar2anda4=ar3∵b1=a1=ab2=b1+a2=a+ar=a(1+r)b3=b2+a3=a(1+r)+ar2=a(1+r+r2)b4=b3+a4=a(1+r+r2)+ar3=a(1+r+r2+r3)⇒ Option (c) is correct  Suggest Corrections  0      Similar questions  Related Videos   Why Do We Need to Manage Our Resources?
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