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Question

# Suppose four distinct positive number a1,a2,a3,a4 are in G.P. Let b1=a1,b2=b1+a2,a3=b2+a3 and b4=b3+a4Statement 1 - The numbers b1,b2,b3,b4 are neither in A.P. nor in G.P.Statement 2 - The numaber b1,b2,b3,b4 are in H.P.

A
Both Statement 1 and Statement 2 are correct and Reason is the correct explanation for Assertion
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B
Both Statement 1 and Statement 2 are correct but Statement 2 is not the correct explanation for Assertion
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C
Statement 1 is correct but Statement 2 is incorrect
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D
Both Statement 1 and Statement 2 are incorrect
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Solution

## The correct option is D Statement 1 is correct but Statement 2 is incorrectb1=a1,b2=b1+a2=a1+a2b3=b2+a3=a1+a2+a3,b4=a1+a2+a3+a4Clearly b1,b2,b3,b4 are neither in A.P. nor in G.P. Hence statement - 1 is true.Also b1,b2,b3,b4 are not in H.P. Hence statement - 2 is false.

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