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Question

Assertion :The equation of hyperbola whose asymptotes are the lines 3x4y+7=0 & 4x+3y+1=0 & which passes through origin is (3x4y+7)(4x+3y+1)=7. Reason: The equation of the pair of asymptotes & hyperbola differ by a constant only.

A
Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
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B
Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
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C
Assertion is correct but Reason is incorrect
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D
Both Assertion and Reason are incorrect
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Solution

The correct option is A Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
Combined equation of the asymptotes is given by ,(3x4y+7)(4x+3y+1)=0
Combined equation of the hyperbola is given by (3x4y+7)(4x+3y+1)+λ=0
(as reason is true) It passes through origin'
λ=7
So equation of hyperbola is (3x4y+7)(4x+3y+1)=7
Hence, option 'A' is correct.

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