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Standard XII

Chemistry

Anomalous Behaviour of Fluorine

Assertion : T...

Question

Assertion : The first ionization energy of $L i$ is less than that of $N a$
Reason : $L i$ is a smaller atom than $N a$

Both assertion and reason are correct and reason is the correct explanation for assertion.

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Both assertion and reason are correct and reason is not the correct explanation for assertion.

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Assertion is correct but reason is incorrect.

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Assertion is incorrect but reason is correct.

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Both assertion and reason are incorrect.

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Solution

The correct option is D Assertion is incorrect but reason is correct.
$L i$ is a smaller atom than $N a$ . Hence, the attraction of nucleus for valence electrons in $L i$ is greater than in $N a$ . Thus $L i$ has higher first ionization energy than nucleus.

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Assertion (A) Order and molecularity are same.

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(a) Both assertion and reason are correct and the reason is correct explanation of assertion
(b) Both assertion and reason are correct, but reason does not explain assertion.
(c) Assertion is correct, but reason is incorrect
(d) Both assertion and reason are incorrect
(e) Assertion is incorrect but reason is correct.

Assertion (A) All collision of reactant molecules lead to product formation.

Reason (R) Only those collisions in which molecules have correct orientation and sufficient kinetic energy lead to compound formation.

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Assertion : The first ionization energy of Li is less than that of NaReason : Li is a smaller atom than Na

The correct option is D Assertion is incorrect but reason is correct.Li is a smaller atom than Na. Hence, the attraction of nucleus for valence electrons in Li is greater than in Na. Thus Li has higher first ionization energy than nucleus.

Assertion : The first ionization energy of $L i$ is less than that of $N a$
Reason : $L i$ is a smaller atom than $N a$

The correct option is D Assertion is incorrect but reason is correct.
$L i$ is a smaller atom than $N a$ . Hence, the attraction of nucleus for valence electrons in $L i$ is greater than in $N a$ . Thus $L i$ has higher first ionization energy than nucleus.