Question

Assertion: When dilute $H_{2}S{O}_4$ is electrolyzed between Pt electrodes, the gas liberated at the anode will be $O_2\left(g\right)$.
Reason: Oxidation potential of $H_{2}O>OxidationpotentialofS{O}_4^{2-}$.

• A. Both Assertion and Reason are true and Reason is the correct explanation of Assertion
• B. Both Assertion and Reason are true but Reason is not the correct explanation of Assertion
• C. Assertion is true but Reason is false
• D. Assertion is false but Reason is true
• E. Both Assertion and Reason are false

Answer 1

The correct option is A Both Assertion and Reason are true and Reason is the correct explanation of Assertion

$O_2\left(g\right)$
Oxidation potential of $H_{2}O>OxidationpotentialofS{O}_4^{2-}$ Hence, oxidation of $H_{2}O$ occurs at anode to give $O_2$ (g).
$H_{2}O\to 2H^{\oplus }+2e^{-}+\frac{1}{2}{O}_2\left(g\right)$