Assign oxidation number to the underlined element in $K_{2} M n - -- - O_{4}$

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Solution

Let x e the oxidation number of Mn in $K_{2} M n O_{4}$
We know that the oxidation no. of $K = + 1 a n d O = - 2$ .
So, $2 (+ 1) + X + 4 (- 2) = 0$
$2 + X - 8 = 0$
$X = + 6$
Hence, the oxidation no. of Mn is +6.

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