Assign oxidation number to the underlined element in $K A l (S - - O_{4})_{2} .12 H_{2} O$

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Solution

Let x be the oxidation state of S in
$K A l (S - - O_{4})_{2} . 12 H_{2} O$
Oxidation no. of known elements are- $K = + 1, A l = + 3, O = - 2, H = + 1$
$+ 1 + 3 + 2 (x + 4 (- 2)) = 0$
$+ 4 + 2 x - 16 = 0$
$2 x = 12$
$x = + 6$
Hence, the oxidation no. of S is +6.

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