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Algebra of Derivatives

Assume size o...

Question

Assume size of integer is 2 Bytes and size of address is 2 bytes.
Consider the following code.
$void main( ) {int a; int b; int c[2]; int (d) [2]; int *e[2]; printf (" %u, %u, %u, %u, %u," sizeof(a), sizeof(b), sizeof(c), sizeof(d), sizeof(e));}$

What is the output produced by the given code?

2, 2, 4, 4, 4

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2, 2, 4, 2, 2

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2, 2, 4, 2, 4

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2, 2, 4, 4, 2

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Solution

The correct option is C $2, 2, 4, 2, 4$
option (d)

$a is integer b is pointer that can hold address of integer c is array of 2 integers d is pointer that can hold address of array of 2 integers e is array of 2 integer pointers sizeof(a) = 2 sizeo f(b) = 2 sizeof(c) = 4 sizeof(d) = 2 sizeof(e) = 4$

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