wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

Assume that a car is able to stop with a retardation of 8 m/s2 and that a driver can react to an emergency in 0.5 sec. Calculate the overall stopping distance of the car for a speed of 72 km/hr of the car

A
25 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
10 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
35 m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
30 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 35 m
Given, reaction time of driver t=0.5 sec
retardation of the car 8 m/s2 and initial velocity of the car u=72 km/hr=20 m/s
Distance covered by the car before application of brake S1=20t=20×0.5=10 m
Now, car begins to move with the retardation
So, distance covered by car before coming to rest is
v2u2=2as 02202=2×8×S2
S2=40016=25 m
Overall stopping distance of the car is
S=S1+S2=10+25=35 m

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Motion Under Constant Acceleration
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon