Assume that a neutron breaks into a proton and an electron. The energy released suring this process is (mass of neutron $= 1.6725 \times 10^{- 27} k g,$
mass od proton $= 1.6725 \times 10^{- 27} k g,$ mass of electron $= 9 \times 10^{- 31} k g)$

0.73 MeV

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7.10 MeV

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6.30 MeV

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5.4 MeV

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Solution

The correct option is A 0.73 MeV
$△ m = (m_{P} + m_{e}) - m_{n}$
$= 9 \times 10^{- 31} k g$
$(m c^{2}) e n e r g y r e l e a s e d = (9 \times 10^{- 31} k g) c^{2} j o u l e s$
$= \frac{9 \times 10^{- 31} \times (3 \times 10^{8})^{2}}{1.6 \times 10^{- 13}} M e v$

$= 0.73 M e v$
Hence option (A) is correct

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Similar questions

Q. Assume that a neutron breaks into a proton and an electron. The energy released during this process is
(Mass of neutron

= 1.6725 \times 10^{- 27} k g

, Mass of proton

= 1.6725 \times 10^{- 27} k g

,Mass of electron

= 9 \times 10^{- 31} k g

)

Q. A neutron breaks into a proton and an electron. Calculate the energy produced in this reaction is MeV. Mass of an electron

= 9 \times 10^{- 31} k g

, mass of proton

= 1.6725 \times 10^{- 27} k g

, mass of neutron

= 1.6747 \times 10^{- 27} k g

, and speed of light

= 3 \times 10^{8} m s^{- 1}

Q. If one takes into account finite mass of the proton, the correction to the binding energy of the hydrogen atom is approximately _____.(mass of proton

1.60 \times 10^{- 27} k g

, mass of electron

= 9.10 \times 10^{- 31} k g

An electron and a proton are detected in a cosmic ray experiment, the first with kinetic energy 10 keV, and the second with 100 keV. Which is faster, the electron or the proton? Obtain the ratio of their speeds. (electron mass = 9.11 × 10^–31 kg, proton mass = 1.67 × 10^–27 kg, 1 eV = 1.60 × 10^–19 J).

Q. A neutron initially at rest, decays into a proton, an electron and an antineutrino. The ejected electron has a momentum of 1.4 × 10⁻²⁶ kg-m/s and the antineutrino 6.4 × 10⁻²⁷ kg-m/s. Find the recoil speed of the proton (a) if the electron and the antineutrino are ejected along the same direction and (b) if they are ejected along perpendicular directions. Mass of the proton = 1.67 × 10⁻²⁷ kg.

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Assume that a neutron breaks into a proton and an electron. The energy released suring this process is (mass of neutron =1.6725×10−27kg,mass od proton =1.6725×10−27kg, mass of electron=9×10−31kg)

The correct option is A 0.73 MeV△m=(mP+me)−mn =9×10−31kg (mc2) energy released=(9×10−31kg)c2 joules=9×10−31×(3×108)21.6×10−13Mev=0.73MevHence option (A) is correct

Assume that a neutron breaks into a proton and an electron. The energy released suring this process is (mass of neutron $= 1.6725 \times 10^{- 27} k g,$
mass od proton $= 1.6725 \times 10^{- 27} k g,$ mass of electron $= 9 \times 10^{- 31} k g)$