1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# Assume that genes a and b are linked and show 40% recombination. If ++ / ++ individual is crossed with ab / ab, then types and proportions of gametes in F1 will be :

A
++ 20% : ab 20% : +b 20% : a + 40%
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
B
++ 50% : ab 50%
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
C
++ 25% : ab 25% : +b 25% : a + 25%
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
D
++ 30% : ab 30% : +b 20% : a + 20%
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

## The correct option is D ++ 30% : ab 30% : +b 20% : a + 20%Genes aandb are incomplete in linkage.Here 40 recombinants are reproduced through crossing over between segments of genes aandb.So the gametes of parental types ++andab should be produced in total frequency of 60 and the total frequencies of recombinants such as +b,b+or+a,a+ should be 40%.Therefore F1 is ++ 30% : ab 30% : +b 20% : a + 20% 20%:a+20%

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
BIOLOGY
Watch in App
Explore more
Join BYJU'S Learning Program