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Question

# Two linked genes a and b show 30% recombination. The indicidual of a dihybrid cross ++/++ ab/ab shall produce gametes as

A
++80; ab 20
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B
++40; ab 40; +a10[ +b10
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C
++35; ab35; +a15; +b15
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D
++50; ab
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Solution

## The correct option is C ++35; ab35; +a15; +b15In the given problem, the recombination is 30%. Hence, it will have 30% crossing over. In this, progeny will be recombinant of both the parents. Hence, there are 15% chances that each progeny will have recombinant genotype, that is +a or +b.The percentage of linkage = 100 - percentage of recombination = 100 -30 = 70%.Hence, there are 35% chances that each progeny will be identical to one of their parents, that is either ab or ++. Thus, the correct answer is option C.

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