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Question

Assume that the decomposition of HNO3 can be represented by the following equation: 4HNO3(g)4NO2(g)+2H2O(g)+O2(g).
The reaction approaches equilibrium at 400 K temperature and 30 atm pressure. At equilibrium, the partial pressure of HNO3 is 2 atm.
The value of Kc ((mol/L)3) at 400 K is:(Use :R=.08atmL/moleK)

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Solution

Ptotal=PHNO3+PNO2+PO2+PH2O

PNO2=4PO2 and PH2O=2PO2

Ptotal=PHNO3+7PO2

302=PO2×7

PO2=287=4 atm

Kp=P4NO2PH2OPO2P4HNO3

Kp=Kc(RT)Δng=Kc(0.08×400)3

Kc=220(32)3=32.

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