Assume that the total surface area of a human body is 1.6 m² and that it radiates like an ideal radiator. Calculate the amount of energy radiated per second by the body if the body temperature is 37°C. Stefan constant σ is 6.0 × 10⁻⁸ W m⁻² K⁻⁴.

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Solution

Given:
Area of the body, A = 1.6 m²
Temperature of the body, T = 310 K
From Stefan-Boltzmann law,

$\frac{Energy radiated}{Time} = σ A T^{4}$

Here, A is the area of the body and $σ$ is the Stefan-Boltzmann constant.

Energy radiated per second = 1.6 × 6 × 10⁻⁸ × (310)⁴
= 886.58 $\approx$ 887 J

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Assume that the total surface area of a human body is 1.6 $m^{2}$ and that it radiates like an ideal radiator. Calculate the amount of enrgy radiated per second by the body if the body temperature is $37^{0}$ C. Stefan constant $σ$ is $6.0 \times 10^{- 8} W m^{- 2} K^{- 4}$ .

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Assume that the total surface area of a human body is 1.6 m2 and that it radiates like an ideal radiator. Calculate the amount of energy radiated per second by the body if the body temperature is 37°C. Stefan constant σ is 6.0 × 10−8 W m−2 K−4.

Given: Area of the body, A = 1.6 m2 Temperature of the body, T = 310 K From Stefan-Boltzmann law, Energy radiatedTime= σAT4 Here, A is the area of the body and σ is the Stefan-Boltzmann constant. Energy radiated per second = 1.6 × 6 × 10−8 × (310)4 = 886.58 ≈887 J

Assume that the total surface area of a human body is 1.6 m² and that it radiates like an ideal radiator. Calculate the amount of energy radiated per second by the body if the body temperature is 37°C. Stefan constant σ is 6.0 × 10⁻⁸ W m⁻² K⁻⁴.