Question

Assuming 1st order diffraction with interparticle distance in a crystal og 0.4nm, calculate the wavelength of X-rays which produce a diffraction angle 20 equal to 0.286 radian for a crystal.

Answer 1

Dear student,
$$\begin{gathered} Bragg\text{'}slaw \\ 2d\sin \theta =n\lambda \\ heren=1,\theta =\frac{0.286}{2}=0.143rad=8.1^0 \\ \lambda =\frac{2d\sin \theta }{n}=2d\sin \theta \\ \lambda =2\times 0.4\times {10}^{-9}\sin (8.1) \\ \lambda =2\times 0.4\times {10}^{-9}\times 0.4 \\ \lambda =0.08\times {10}^{-9}=8\times {10}^{-11}m \end{gathered}$$

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