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Standard XII

Chemistry

Zero Order Reaction

Assuming an e...

Question

Assuming an elementry reaction, $H_{2} O_{2} + 3 I^{-} + 2 H^{+} \to 2 H_{2} O + {I_{3}}^{-}$ . What will be the effect on the rate of this reaction, by doubling the concentration of $I^{-}$ without changing the order?

The rate would increase by a factor of 3

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The rate would increase by a factor of 8

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The rate would decrease by a factor of 1/3

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The rate would increase by a factor of 9

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Solution

The correct option is A The rate would increase by a factor of 3
$H_{2} O_{2} + 3 I^{-} + 2 H^{+} \to 2 H_{2} O_{2} + I_{3}^{-}$
Rate of reaction is directly $\propto$ ${[I]}^{\frac{3}{2}}$ .
So, if the reaction of $I^{-}$ is doubled, the rate of reaction will increase by factor of $3$ .

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Similar questions

Q. The stoichiometric equation for the oxidation of bromide ions by hydrogen peroxide in acid solution is

2 B r (a q) + H_{2} O_{2} (a q) + {2 H}^{+} (a q) ⟶ {B r}_{2} (ℓ) + 2 H_{2} O (ℓ)

.
Since the reaction does not occur in one stage the rate equation does not correspond to this stochiometric equation but is rate =

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Assuming an elementry reaction, H2O2+3I−+2H+→2H2O+I3−. What will be the effect on the rate of this reaction, by doubling the concentration of I− without changing the order?

The correct option is A The rate would increase by a factor of 3H2O2+3I−+2H+→2H2O2+I−3 Rate of reaction is directly ∝ [I]32. So, if the reaction of I− is doubled, the rate of reaction will increase by factor of 3.

Assuming an elementry reaction, $H_{2} O_{2} + 3 I^{-} + 2 H^{+} \to 2 H_{2} O + {I_{3}}^{-}$ . What will be the effect on the rate of this reaction, by doubling the concentration of $I^{-}$ without changing the order?

The correct option is A The rate would increase by a factor of 3
$H_{2} O_{2} + 3 I^{-} + 2 H^{+} \to 2 H_{2} O_{2} + I_{3}^{-}$
Rate of reaction is directly $\propto$ ${[I]}^{\frac{3}{2}}$ .
So, if the reaction of $I^{-}$ is doubled, the rate of reaction will increase by factor of $3$ .