Question

Assuming complete dissociation of $H_{2}S{O}_4$ as $(H_{2}S{O}_4+2H_{2}O\to 2H_2{O}^{+}+S{O}_4^{2-})$. The number of $H_3{O}^{+}$ ions in 10 mL of $0.5N{H}_{2}S{O}_4$ is :

• A. $3.01\times {10}^{21}$
• B. $1.5\times {10}^{21}$
• C. $6.02\times {10}^{21}$
• D. $3.01\times {10}^{22}$

Answer 1

The correct option is A $3.01\times {10}^{21}$