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Question

Assuming fully decomposed, the volume of CO2 released at STP on heating 9.85g of BaCO3 (atomic mass, Ba=137) will be:

A
1.12L
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B
0.84L
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C
2.24L
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D
4.06L
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Solution

The correct option is A 1.12L
On decomposition BaCO3 liberates CO2 as

BaCO3197gBaO+CO222.4L at STP

197g BaCO3 gives 22.4L of CO2 at STP

9.85g BaCO3 will give CO2=22.4×9.85197=1.12L

Hence, the correct option is A

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