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Byju's Answer
Standard IX
Mathematics
Total Surface Area of a Cuboid
Assuming pool...
Question
Assuming pool is
15
m
in length,
12
m
in breadth and
2
m
in depth. Find the cost of cementing the floor and wall at the rate of
R
s
.15
per
s
q
.
m
.
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Solution
Length of pool
(
l
)
=
15
m
Breadth of pool
(
b
)
=
12
m
Height of pool
(
h
)
=
2
m
Now,
Area of floor
=
l
×
b
=
15
×
12
=
180
m
2
Area of walls
=
2
h
(
l
+
b
)
=
2
×
2
(
15
+
12
)
=
4
×
27
=
108
m
2
Total area
=
108
+
180
=
288
m
2
Cost of cementing
=
R
s
.
15
per square meter
Therefore,
Cost of cementing the floor and wall of pool
=
15
×
288
=
R
s
.
4320
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