Assuming that a year consits of 365 days, the probability that a group of 30 people have all different birthdays is
A
36536530
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B
3036530
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C
365P3036530
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D
30P3036530
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Solution
The correct option is B365P3036530 The each person has 365 days as options for his birthday n(S)=36530 For unique birthdays, choose any 30 days and assign each person each day n(E)=P(365,30) P=365C3036530