The correct option is B 1 g
Given,
Power of fission reactor is, P=106 W=106 Js−1
Time required =t=1 day=24×36×102=8.64×104 s
Energy produced, U=Pt=106×8.64×104=8.64×1010 J
Energy released per fission of 92U235 is,
200 MeV=200×106×1.6×10−19=32×10−12 J
The number of 92U235 atoms used is,
=8.64×101032×10−12=27×1020
The mass of 92U235 required is,
m=(2356×1023)(27×1020)=1.058 g≃1 g
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Hence, (B) is the correct answer.