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Standard XII

Physics

Distance

Assuming the ...

Question

Assuming the masses of the pulley and the thread, as well as the friction, to be negligible, find the acceleration of the load $m_{1}$ relative to the car.

w_{1}^{'} = \frac{2 m_{1} - 2 m_{2}}{m_{1} + m_{2}} (g - w_{0})

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w_{1}^{'} = \frac{m_{1} - m_{2}}{m_{1} + m_{2}} (g - w_{0})

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w_{1}^{'} = \frac{2 m_{1} - m_{2}}{m_{1} + m_{2}} (g - w_{0})

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w_{1}^{'} = \frac{m_{1} - 2 m_{2}}{m_{1} + m_{2}} (g - w_{0})

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Solution

The correct option is B $w_{1}^{'} = \frac{m_{1} - m_{2}}{m_{1} + m_{2}} (g - w_{0})$
Here we assume that $m_{1} > m_{2}$
From FBD,
$m_{1} w^{'} = m_{1} (g - w_{0}) - T . . . . . (1)$
$m_{2} w^{'} = T - m_{2} (g - w_{0}) . . . . . (2)$
$(1) + (2), (m_{1} + m_{2}) w^{'} = (m_{1} - m_{2}) (g - w_{0})$
$w^{'} = \frac{m_{1} - m_{2}}{m_{1} + m_{2}} (g - w_{0})$

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Assuming the masses of the pulley and the thread, as well as the friction, to be negligible, find the acceleration of the load m1 relative to the car.

The correct option is B w′1=m1−m2m1+m2(g−w0)Here we assume that m1>m2From FBD,m1w′=m1(g−w0)−T.....(1)m2w′=T−m2(g−w0).....(2)(1)+(2),(m1+m2)w′=(m1−m2)(g−w0)w′=m1−m2m1+m2(g−w0)

Assuming the masses of the pulley and the thread, as well as the friction, to be negligible, find the acceleration of the load $m_{1}$ relative to the car.