At 0∘C and one atm pressure, a gas occupies 100cc. If the pressure is increased to one and a half time and temperature is increased by one-third of absolute temperature, then final volume of the gas will be :
A
80cc
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
88.9cc
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
66.7cc
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
100cc
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is D88.9cc Initial temperature T1=0oC=273.15K
Initial pressure P1=1atm
Initial volume V1=100cc Final temperature T2=(1+13)×273.15=364.2K Final pressure P2=112×1=1.5atm Final volume V2= ?? P1V1T1=P2V2T2
1atm×100cc273.15K=1.5atm×V2364.2K
V2=88.9cc Hence, the final volume of the gas will be 88.9 cc.