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pH of Acids and Bases

At 0oC if t...

Question

At $0^{o} C$ if the product $[H^{+}] [O H^{-}]$ of water is $10^{- 15} m o l^{2} / d m^{6}$ then the pH at $0^{o} C$ of 0.01 $m o l / d m^{3}$ solution of NaOH is :

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Solution

The correct option is A 13
At $0^{o} C$ temperature $0.0 = 1 m o l / d m^{3}$ solution of NaOH means that solution has $0.01 m o l / d m^{3}$ concentration of $O H^{-}$
According to question, we know
$[H^{+}] [O H^{-}] = 10^{- 15}$
$p H + p O H = 15$ (on taking log)
$p O H = - l o g 10^{- 2} = 2$
$p H = 15 - 2 = 13$

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