Question

At ${10}^{\circ }C,$ the osmotic pressure of urea solution is 500 mm. The solution is diluted and the temperature is raised to ${10}^{\circ }C,$ when the osmotic pressure is found to be 105.3 mm. If the relationship between final volume and original volume given by $(V_{final}=x.V_{original})$. Find the value of x

• A. $3$
• B. $4$
• C. $5$
• D. $6$

Answer 1

The correct option is C $5$

The osmotic pressure, $\Pi$ is directly proportional to the concentration and inversely proportional to volume when temperature is held constant.

Given that at ${10}^{o}C$, the osmotic pressure of urea solution is $500$ mm.
$\frac{{\Pi }_f}{{\Pi }_i}=\frac{V_i}{V_f}$
$x=\frac{V_f}{V_i}=\frac{{\Pi }_i}{{\Pi }_f}=\frac{500}{105.3}\simeq 5$