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Byju's Answer
Standard XII
Chemistry
Law of Mass Action
At 1000 K, th...
Question
At 1000 K, the equilibrium constants for the following
equilibrium are
K
1
and
K
2
.
C
O
C
l
2
(
g
)
⇌
C
O
(
g
)
+
C
l
2
(
g
)
;
K
1
=
0.329
2
C
O
(
g
)
+
O
2
(
g
)
⇌
2
C
O
2
(
g
)
;
K
2
=
2.24
×
10
22
For the equilibrium,
2
C
O
C
l
2
(
g
)
+
O
2
(
g
)
⇌
2
C
O
2
(
g
)
+
2
C
l
2
(
g
)
, the equilibrium constant
K
3
is:
A
2.424
×
10
22
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B
2.424
×
10
21
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C
4
.84
×
10
2
0
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D
2.424
×
10
20
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Solution
The correct option is
B
2.424
×
10
21
C
O
C
l
2
(
g
)
⇌
C
O
(
g
)
+
C
l
2
(
g
)
;
K
1
=
0.329
2
C
O
(
g
)
+
O
2
(
g
)
⇌
2
C
O
2
(
g
)
;
K
2
=
2.24
×
10
22
For the reaction,
2
C
O
C
l
2
(
g
)
+
O
2
(
g
)
⇌
2
C
O
2
(
g
)
+
2
C
l
2
(
g
)
∴
K
3
=
(
K
1
)
2
×
K
2
K
3
=
(
0.329
)
2
×
2.24
×
10
22
=
0.2424
×
10
22
=
2.424
×
10
21
Hence, option B is correct.
Suggest Corrections
0
Similar questions
Q.
C
O
C
l
2
(
g
)
⇌
C
O
(
g
)
+
C
l
2
(
g
)
;
K
1
=
0.329
2
C
O
(
g
)
+
O
2
(
g
)
⇌
2
C
O
2
(
g
)
;
K
2
=
2.24
×
10
22
Calculate the equilibrium constant for the reaction given below from the data given above at
1000
K
:
2
C
O
C
l
2
(
g
)
+
O
2
(
g
)
⇌
2
C
O
2
(
g
)
+
C
l
2
(
g
)
Q.
The equilibrium constants for the following reactions at
1400
K
are given:
2
H
2
O
(
g
)
⇌
2
H
2
(
g
)
+
O
2
(
g
)
;
K
1
=
2.1
×
10
−
13
2
C
O
2
(
g
)
⇌
2
C
O
(
g
)
+
O
2
(
g
)
;
K
2
=
1.4
×
10
−
12
Then, the equilibrium constant
K
for the reaction,
H
2
(
g
)
+
C
O
2
(
g
)
⇌
C
O
(
g
)
+
H
2
O
(
g
)
, is:
Q.
Calculate the equilibrium constant for the reaction
H
2
(
g
)
+
C
O
2
(
g
)
⇌
H
2
O
(
g
)
+
C
O
(
g
)
at
1395
K
, if the equilibrium constants at
1395
K
for following are:
2
H
2
O
(
g
)
⇌
2
H
2
+
O
2
(
g
)
;
K
1
=
2.1
×
10
−
13
2
C
O
2
(
g
)
⇌
2
C
O
(
g
)
+
O
2
(
g
)
;
K
2
=
1.4
×
10
−
12
.
Q.
For the reaction in equilibrium
(I)
C
O
(
g
)
+
1
2
O
2
(
g
)
⇌
C
O
2
(
g
)
(II)
2
C
O
(
g
)
+
O
2
(
g
)
⇌
2
C
O
2
(
g
)
Then,
Equilibrium constant
Free energy change
K
1
Δ
G
1
K
2
Δ
G
2
Q.
Equilibrium constants for the following reaction at 1200 K are given.
2
H
2
O
(
g
)
⇋
2
H
2
(
g
)
+
O
2
(
g
)
;
K
1
=
6.4
×
10
−
8
2
C
O
2
(
g
)
⇋
2
C
O
(
g
)
+
O
2
(
g
)
;
K
2
=
1.6
×
10
−
6
The equilibrium constant for the reaction
H
2
(
g
)
+
C
O
2
(
g
)
⇋
C
O
(
g
)
+
H
2
O
(
g
)
at 1200 K will be:
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