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Elementary and Complex Reactions

At 1000 K, ...

Question

At $1000 K$ , the pressure of iodine gas is found to be 0.112 atm due to partial dissociation. Had there been no dissociation, the pressure would have been 0.074 atm. $K_{p}$ for reaction : $I_{2} (g) ⇌ 2 I (g)$ is x. $100 x$ is:

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Solution

$I_{2} (g) \to 2 I (g)$
At $t = 0; 0.074$ 0
At eqm.; $(0.074 - p) 2 p$

Total= $0.074 - p + 2 p = 0.112$
$p = 0.112 - 0.074 = 0.038 a t m$

$K_{P} = \frac{P (I)^{2}}{P (I_{2})} = \frac{(2 p)^{2}}{0.074 - p}$

$K_{P} = \frac{0.00576}{0.036} = 0.16$ atm

$100 x = 16$

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